40 lines
1.4 KiB
TypeScript
40 lines
1.4 KiB
TypeScript
/**
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* 实施 / 规划会话 resume 的落点决策。纯函数，不碰 vscode API，便于单测。
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*
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* 角色由调用方明确传入，不从「有没有 cwd」反推：worktree 被清理后
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* 工单里的 worktreePath 会清空，靠 cwd 推断会把实施会话误判成规划。
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*/
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export type ResumeKind = 'implement' | 'brainstorm'
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export function resumeSessionRole(kind: ResumeKind): '实施' | '规划' {
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return kind === 'implement' ? '实施' : '规划'
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}
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export function resumeTerminalName(kind: ResumeKind, sessionId: string, issueNumber?: number): string {
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return issueNumber !== undefined
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? `issue-${issueNumber}-${resumeSessionRole(kind)}`
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: `Claude · ${sessionId.slice(0, 8)}`
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}
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export interface ResumeCwdInput {
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kind: ResumeKind
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workspaceRoot: string
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/** 已解析成绝对路径的 worktree；工单没记就 undefined */
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worktreeAbs?: string
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worktreeExists: boolean
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}
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export interface ResumeCwdPlan {
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cwd: string
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/** 实施会话但 worktree 已不在磁盘上（含工单里没记 worktreePath 的情况） */
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worktreeMissing: boolean
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}
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export function planResumeCwd(input: ResumeCwdInput): ResumeCwdPlan {
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if (input.kind !== 'implement')
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return { cwd: input.workspaceRoot, worktreeMissing: false }
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if (input.worktreeAbs && input.worktreeExists)
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return { cwd: input.worktreeAbs, worktreeMissing: false }
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return { cwd: input.workspaceRoot, worktreeMissing: true }
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}
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